4sin^2(2x)-7cos(2x)=2

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Solution for 4sin^2(2x)-7cos(2x)=2 equation:


Simplifying
4sin2(2x) + -7cos(2x) = 2

Remove parenthesis around (2x)
4in2s * 2x + -7cos(2x) = 2

Reorder the terms for easier multiplication:
4 * 2in2s * x + -7cos(2x) = 2

Multiply 4 * 2
8in2s * x + -7cos(2x) = 2

Multiply in2s * x
8in2sx + -7cos(2x) = 2

Remove parenthesis around (2x)
8in2sx + -7cos * 2x = 2

Reorder the terms for easier multiplication:
8in2sx + -7 * 2cos * x = 2

Multiply -7 * 2
8in2sx + -14cos * x = 2

Multiply cos * x
8in2sx + -14cosx = 2

Reorder the terms:
-14cosx + 8in2sx = 2

Solving
-14cosx + 8in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8in2sx' to each side of the equation.
-14cosx + 8in2sx + -8in2sx = 2 + -8in2sx

Combine like terms: 8in2sx + -8in2sx = 0
-14cosx + 0 = 2 + -8in2sx
-14cosx = 2 + -8in2sx

Divide each side by '-14osx'.
c = -0.1428571429o-1s-1x-1 + 0.5714285714in2o-1

Simplifying
c = -0.1428571429o-1s-1x-1 + 0.5714285714in2o-1

Reorder the terms:
c = 0.5714285714in2o-1 + -0.1428571429o-1s-1x-1

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